Resonance and Q Factor

In the following circuit the readings of AC voltmeters and ammeters will be respectively-

Draw a current versus frequency graph for parallel resonant circuit.

The current is minimum in _____ LCR circuit?

The current is minimum in parallel LCR circuit?

Why the current is minimum in parallel LCR circuit?

What is the value of current in RLC parallel circuit at resonance frequency

In series RLC circuit, at resonance condition impedance is purely resistive, and it is equal to _____.

The resonant frequency of the series LCR circuit is expressed as. f_r = 1/2π√(LC)

What is meant by resonance in an LCR circuit?

Half power point frequencies for which the power in the circuit is half of the ___________________ power in the circuit.

The half power point is commonly used definition for the _____ frequency.

The relationship between power and frequency is inversely proportional to each other.

What is half power point frequency?

The inductance of the oscillatory circuit of the radio station is $10 \mathrm{mH}$ and its capacitance is $0.25 \mathrm{\mu F}$. Taking the effect of resistance negligible, wavelength of the broadcasted waves will be (velocity of light $=3.0\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1},\mathrm{ }\mathrm{\pi }=3.14$)

In LCR series circuit $L=4H, C=36 \mu F \mathrm{and} R=16\Omega$, then bandwidth of resonance is 

The bandwidth of resonance in the $L-C-R$  A.C. circuit is proportional to inductance.

For an RLC circuit driven with voltage of amplitude $v_m$ and frequency ${\text{ω}}_0=\frac{1}{\sqrt{LC}}$ the current exhibits resonance. The quality factor, $Q$ is given by

The inductance of the oscillatory circuit of the radio station is $10 \mathrm{mH}$ and its capacitance is $0.25 \mathrm{\mu F}$. Taking the effect of resistance negligible, wavelength of the broadcasted waves will be (velocity of light $=3.0\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1},\mathrm{ }\mathrm{\pi }=3.14$)

A transmitting station releases waves of wavelength $960 \mathrm{m}.$ A capacitor of $256 \mu \mathrm{F}$ is used in the resonant circuit. The self inductance of coil necessary for resonance is $\times {10}^{-8}\mathrm{H}.$

A series LCR circuit containing a resistance of $120 \mathrm{\Omega }$ has an angular resonance frequency $4\times {10}^5 \mathrm{rad} {\mathrm{s}}^{-1}.$ At resonance the voltage across resistance and inductance are $60 \mathrm{V}$ and $40 \mathrm{V}$ respectively. At frequency $\omega =\mathrm{X}\times {10}^5 \mathrm{rad} {\mathrm{s}}^{-1}$ the current in the circuit lags the voltage by $45°.$ Find the value of $X.$